Model Answer
0 min readIntroduction
In operational management, understanding the reliability and error rates of different processes or personnel is crucial for quality control and efficiency. This scenario presents a typical problem encountered in organizations where tasks are distributed among multiple individuals or departments. The problem requires us to determine the probability that an error in processed mail originated from a specific clerk, given that an error has been detected. This is a classic application of Bayesian inference, a statistical method for updating beliefs based on new evidence. The Postmaster's inquiry necessitates the application of Bayes' Theorem to ascertain the probabilities of each clerk being responsible for the error.
Understanding the Problem
Let's define the events:
- C1: The mail was processed by Clerk 1.
- C2: The mail was processed by Clerk 2.
- C3: The mail was processed by Clerk 3.
- E: The mail has an error.
We are given the following probabilities:
- P(C1) = 0.40 (Probability that Clerk 1 processed the mail)
- P(C2) = 0.35 (Probability that Clerk 2 processed the mail)
- P(C3) = 0.25 (Probability that Clerk 3 processed the mail)
- P(E|C1) = 0.04 (Probability of an error given the mail was processed by Clerk 1)
- P(E|C2) = 0.06 (Probability of an error given the mail was processed by Clerk 2)
- P(E|C3) = 0.03 (Probability of an error given the mail was processed by Clerk 3)
We need to find P(C1|E), P(C2|E), and P(C3|E) – the probabilities that the mail was processed by each clerk, given that it has an error.
Bayes' Theorem
Bayes' Theorem states:
P(A|B) = [P(B|A) * P(A)] / P(B)
In our case, we need to calculate P(B), the probability of an error occurring, which can be calculated using the law of total probability:
P(E) = P(E|C1) * P(C1) + P(E|C2) * P(C2) + P(E|C3) * P(C3)
Calculating P(E)
P(E) = (0.04 * 0.40) + (0.06 * 0.35) + (0.03 * 0.25)
P(E) = 0.016 + 0.021 + 0.0075
P(E) = 0.0445
Calculating P(C1|E), P(C2|E), and P(C3|E)
P(C1|E)
P(C1|E) = [P(E|C1) * P(C1)] / P(E)
P(C1|E) = (0.04 * 0.40) / 0.0445
P(C1|E) = 0.016 / 0.0445
P(C1|E) ≈ 0.3596
P(C2|E)
P(C2|E) = [P(E|C2) * P(C2)] / P(E)
P(C2|E) = (0.06 * 0.35) / 0.0445
P(C2|E) = 0.021 / 0.0445
P(C2|E) ≈ 0.4719
P(C3|E)
P(C3|E) = [P(E|C3) * P(C3)] / P(E)
P(C3|E) = (0.03 * 0.25) / 0.0445
P(C3|E) = 0.0075 / 0.0445
P(C3|E) ≈ 0.1685
Summary of Probabilities
| Clerk | Probability (Given Error) |
|---|---|
| C1 | 0.3596 |
| C2 | 0.4719 |
| C3 | 0.1685 |
Conclusion
The Postmaster can conclude that, given an error in the processed mail, there is approximately a 35.96% probability it was processed by Clerk 1, a 47.19% probability it was processed by Clerk 2, and a 16.85% probability it was processed by Clerk 3. These probabilities highlight that Clerk 2 is the most likely source of errors, despite having a moderate error rate, due to processing the second-highest volume of mail. This information can be used to target training or process improvements to reduce errors and improve overall efficiency.
Answer Length
This is a comprehensive model answer for learning purposes and may exceed the word limit. In the exam, always adhere to the prescribed word count.