The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be doubled of the sum of the ages of his sons. The father’s present age is

To solve this, let the current sum of the ages of the two sons be S. According to the first condition, the father's present age is 3S. In five years, the father's age will be 3S + 5. Each of the two sons will also be 5 years older, so the new sum of their ages will be S + 10. According to the second condition, the father's age in five years will be double the new sum of the sons' ages. This gives the equation: 3S + 5 = 2 multiplied by (S + 10). Solving the equation: 3S + 5 = 2S + 20 3S - 2S = 20 - 5 S = 15 The current sum of the sons' ages is 15. Since the father's present age is 3S, his age is 3 multiplied by 15, which equals 45 years. Therefore, option B is correct.