Three Dice (each having six faces with each face having one number from 1 to 6) are rolled. What is the number of possible put comes such that at least one dice shows the number 2?

To find the number of outcomes where at least one die shows the number 2, it is easiest to subtract the outcomes where no die shows a 2 from the total possible outcomes. Total outcomes: Since each of the three dice has 6 faces, the total number of possible outcomes is 6 times 6 times 6, which equals 216. Outcomes with no 2: If no die shows the number 2, then each die has only 5 remaining possibilities (1, 3, 4, 5, or 6). The number of such outcomes is 5 times 5 times 5, which equals 125. Outcomes with at least one 2: Subtract the outcomes with no 2 from the total outcomes. 216 minus 125 equals 91. Therefore, there are 91 possible outcomes where at least one die shows the number 2. Option C is the correct answer.