UPSC Prelims 2014·CSAT·Quantitative Aptitude·Arithmetic

The following table shows the marks obtained by two students in different subjects: | Subjects | Student A | Max Marks A | Student B | Max Marks B | | English | 60 | 100 | 80 | 150 | | Psychology | 70 | 100 | 70 | 100 | | History | 30 | 100 | 60 | 100 | | Sanskrit | 50 | 50 | 15 | 25 | The difference in the mean aggregate percentage marks of the students is

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Last updated 23 May 2026, 3:31 pm IST
  1. A2.50%
  2. B13.75%
  3. C1.25%
  4. DZeroCorrect

Explanation

To find the difference in the mean aggregate percentage marks, we first calculate the total aggregate percentage for each student. The aggregate percentage is calculated as (Total marks obtained / Total maximum marks) * 100. For Student A: Total marks obtained = 60 (English) + 70 (Psychology) + 30 (History) + 50 (Sanskrit) = 210 Total maximum marks = 100 (English) + 100 (Psychology) + 100 (History) + 50 (Sanskrit) = 350 Aggregate percentage for Student A = (210 / 350) * 100 = (3/5) * 100 = 60% For Student B: Total marks obtained = 80 (English) + 70 (Psychology) + 60 (History) + 15 (Sanskrit) = 225 Total maximum marks = 150 (English) + 100 (Psychology) + 100 (History) + 25 (Sanskrit) = 375 Aggregate percentage for Student B = (225 / 375) * 100 = (9 * 25 / 15 * 25) * 100 = (9/15) * 100 = (3/5) * 100 = 60% The difference in their mean aggregate percentage marks is: Difference = Aggregate percentage for Student A - Aggregate percentage for Student B Difference = 60% - 60% = 0% Analysis of Options: A) 2.50%: Incorrect, as the calculated difference is 0%. B) 13.75%: Incorrect, as the calculated difference is 0%. C) 1.25%: Incorrect, as the calculated difference is 0%. D) Zero: Correct, as both students have an aggregate percentage of 60%, resulting in a difference of 0%. The final answer is D.
Quantitative Aptitude: The following table shows the marks obtained by two students in different subjects: | Subjects | Student A | Max Marks A

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