A biology class at Central High School predicted that a local population of animals will double in size every 12 years. The population at the beginning of 2021 was estimated to be 50 animals. If P represents the population n years after 2021, then which of the following equations represents the class model of the population over time?
- AP = 12 + 50n
- BP = 50 + 12n
- CP = 50(2)¹²n
- DP = 50(2)ⁿ / 12Correct
Explanation
The problem describes exponential growth, where the population doubles every 12 years. The initial population is 50.
- Identify the type of growth: The phrase "doubles in size every 12 years" indicates exponential growth, not linear growth.
- General form of exponential growth: For a population that doubles every 'd' units of time, the formula is P = P0 * (2)^(t/d), where P0 is the initial population, t is the time elapsed, and d is the doubling period.
- Apply the given values:
- Initial population (P0) = 50
- Doubling period (d) = 12 years
- Time elapsed (t) = n years
- Substitute these values into the formula: P = 50 * (2)^(n/12).
Let's evaluate the options:
A) P = 12 + 50n: This represents linear growth. If n=0, P=12, which is incorrect as the initial population is 50. B) P = 50 + 12n: This also represents linear growth. If n=12, P = 50 + 1212 = 194. However, after 12 years, the population should double to 502 = 100. So, this is incorrect. C) P = 50(2)^12n: This is an exponential model, but the exponent is incorrect. If n=12, P = 50(2)^(1212) = 50(2)^144, which is an extremely large number, not 100. This model would imply doubling 12 times per year, or a much faster growth rate. D) P = 50(2)^(n/12): This matches the derived exponential growth formula. * If n=0 (beginning of 2021), P = 50(2)^(0/12) = 50(2)^0 = 501 = 50. (Correct initial population) * If n=12 (after 12 years), P = 50(2)^(12/12) = 50(2)^1 = 50*2 = 100. (Correct doubling)
Therefore, option D correctly represents the class model of the population over time.
The final answer is D

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