UPSC MainsZOOLOGY-PAPER-II201410 Marks
हिंदी में पढ़ें
Q5.

Complete the table given below by inserting 0, 1, ½ or for the probability of each genotype of progeny for each type of mating. Give reasons.

How to Approach

This question tests the understanding of Mendelian genetics and probability calculations in breeding. The approach involves systematically analyzing each mating scenario (AA x aa, Aa x Aa, Aa x aa) and applying the principles of segregation and independent assortment to determine the genotypic ratios of the offspring. A Punnett square is the most effective tool for visualizing and calculating these probabilities. The answer should clearly present the Punnett squares and the resulting probabilities in the table format requested. Emphasis should be on explaining the reasoning behind each probability.

Model Answer

0 min read

Introduction

Mendelian genetics, the foundation of modern genetics, explains how traits are inherited from parents to offspring. The core principles include the Law of Segregation, stating that allele pairs separate during gamete formation, and the Law of Independent Assortment, which applies to genes on different chromosomes. Understanding these laws allows us to predict the probability of specific genotypes and phenotypes in offspring. This question assesses the ability to apply these principles to simple monohybrid crosses and accurately represent the probabilities of different genotypes. Accurate prediction of inheritance patterns is crucial in fields like animal breeding, plant breeding, and human genetic counseling.

Understanding the Mating Scenarios and Probability Calculations

We will analyze three different mating scenarios: homozygous dominant (AA) x homozygous recessive (aa), heterozygous (Aa) x heterozygous (Aa), and heterozygous (Aa) x homozygous recessive (aa). For each scenario, we will construct a Punnett square to determine the possible genotypes of the offspring and their corresponding probabilities.

Scenario 1: AA x aa

This is a cross between a homozygous dominant individual and a homozygous recessive individual. All offspring will be heterozygous (Aa).

a a
A Aa Aa
A Aa Aa

Therefore, the probability of genotype Aa is 1.

Scenario 2: Aa x Aa

This is a cross between two heterozygous individuals. The possible genotypes of the offspring are AA, Aa, and aa.

A a
A AA Aa
a Aa aa

From the Punnett square, we can see that:

  • The probability of genotype AA is ¼ (0.25).
  • The probability of genotype Aa is ½ (0.5).
  • The probability of genotype aa is ¼ (0.25).

Scenario 3: Aa x aa

This is a cross between a heterozygous individual and a homozygous recessive individual. The possible genotypes of the offspring are Aa and aa.

a a
A Aa Aa
a aa aa

From the Punnett square, we can see that:

  • The probability of genotype Aa is ½ (0.5).
  • The probability of genotype aa is ½ (0.5).

Completed Table

Mating AA Aa aa
AA x aa 0 1 0
Aa x Aa ¼ (0.25) ½ (0.5) ¼ (0.25)
Aa x aa 0 ½ (0.5) ½ (0.5)

Conclusion

In conclusion, accurately predicting the genotypic ratios of offspring requires a thorough understanding of Mendelian genetics and the application of tools like Punnett squares. The probabilities calculated for each mating scenario demonstrate the principles of segregation and independent assortment. These principles are fundamental to understanding inheritance patterns and have significant implications in various biological disciplines. Further complexities arise with incomplete dominance, codominance, and polygenic inheritance, but the foundational principles remain the same.

Answer Length

This is a comprehensive model answer for learning purposes and may exceed the word limit. In the exam, always adhere to the prescribed word count.

Additional Resources

Key Definitions

Genotype
The genetic constitution of an organism, referring to the specific alleles it possesses for a particular trait.
Allele
One of two or more alternative forms of a gene that arise by mutation and are found at the same place on a chromosome.

Key Statistics

Approximately 700 genetic disorders are known to be caused by single gene mutations (as of 2023).

Source: National Institutes of Health (NIH), USA

Around 1 in 200 people are born with a single-gene disorder (knowledge cutoff 2023).

Source: March of Dimes

Examples

Cystic Fibrosis

Cystic fibrosis is an autosomal recessive genetic disorder. If both parents are carriers (Aa), there is a 25% chance their child will have the disease (aa), a 50% chance the child will be a carrier (Aa), and a 25% chance the child will be unaffected (AA).

Frequently Asked Questions

What is the difference between genotype and phenotype?

Genotype refers to the genetic makeup of an organism, while phenotype refers to the observable characteristics resulting from the interaction of the genotype with the environment.

Topics Covered

BiologyGeneticsMendelian GeneticsProbabilityInheritance