Consider the series given below: 4/12/95, 1/1/96, 29/1/96, 26/2/96... The next term of the series is
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UPSC Civil Services preparation
- A24/3/96
- B25/3/96Correct
- C26/3/96
- D27/3/96
Explanation
To find the next term, we need to determine the number of days between the consecutive dates in the series.
1. From 4/12/95 to 1/1/96:
December has 31 days. Remaining days in December are 31 minus 4, which is 27. Adding the 1 day of January gives a total interval of 28 days.
2. From 1/1/96 to 29/1/96:
29 minus 1 equals 28 days.
3. From 29/1/96 to 26/2/96:
January has 31 days. Remaining days in January are 31 minus 29, which is 2. Since 1996 is a leap year, February has 29 days. Adding 24 days of February to the 2 remaining days of January would not work, but adding the 26 days of February to the 2 days of January gives exactly 28 days.
The constant interval is 28 days. To find the next term, add 28 days to 26/2/96:
February 1996 has 29 days. Remaining days in February are 29 minus 26, which is 3 days. To complete the 28 day interval, we need 25 more days (28 minus 3).
Therefore, 25 days into the next month is 25/3/96.
The correct option is B.

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