UPSC Prelims 1998·GS1·science-and-technology·science and technology

A ball is dropped from the top of a high building with a constant acceleration of 9.8 m/s². What will be its velocity after 3 seconds?

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Last updated 23 May 2026, 3:31 pm IST
  1. A9.8 m/s
  2. B19.6 m/s
  3. C29.4 m/sCorrect
  4. D39.2 m/s

Explanation

To solve this problem, we use the first equation of motion: Velocity equals Initial Velocity plus (Acceleration multiplied by Time). When a ball is dropped from a height, its initial velocity is 0 m/s. The acceleration due to gravity is given as 9.8 m/s per second. The time elapsed is 3 seconds. By multiplying the acceleration (9.8) by the time (3), we get 29.4. Therefore, the velocity of the ball after 3 seconds will be 29.4 m/s. This makes option C the correct answer.
science-and-technology: A ball is dropped from the top of a high building with a constant acceleration of 9.8 m/s². What will be its velocity af
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