Consider the volumes of the following: 1. A parallelepiped of length 5 cm, breadth 3 cm and height 4 cm 2. A cube of each side 4 cm 3. A cylinder of radius 3 cm and length 3 cm 4. A sphere of radius 3 cm The volumes of these in the decreasing order is

To find the decreasing order of the volumes, we calculate each individually using the approximate value of pi as 3.14. 1. Parallelepiped volume is length times breadth times height. 5 times 3 times 4 equals 60 cubic cm. 2. Cube volume is side cubed. 4 times 4 times 4 equals 64 cubic cm. 3. Cylinder volume is pi times radius squared times length. 3.14 times 3 squared times 3 equals 3.14 times 27, which is approximately 84.78 cubic cm. 4. Sphere volume is four-thirds times pi times radius cubed. 4/3 times 3.14 times 3 cubed equals 4 times 3.14 times 9, which is approximately 113.04 cubic cm. Comparing the results: Sphere (113.04) is greater than Cylinder (84.78), which is greater than Cube (64), which is greater than Parallelepiped (60). The decreasing order is IV, III, II, I. Therefore, option D is correct.