Out of 120 applications for a post, 70 are male and 80 have a driver's license. What is the ratio between the minimum to maximum number of males having driver's license?

Here's a brief explanation: 1. **Identify the total groups:** * Total applicants = 120 * Males = 70 * Females = 120 - 70 = 50 * People with driver's license (DL) = 80 * People without driver's license (NDL) = 120 - 80 = 40 2. **Calculate the minimum number of males with DL:** * To minimize males with DL, we must maximize the number of females with DL. * The maximum number of females with DL can be 50 (since there are only 50 females). * If 50 females have a DL, then the remaining people with DL must be male. * Minimum males with DL = Total DL - Max Females with DL = 80 - 50 = 30. * (Alternatively: To minimize males with DL, maximize males without DL. The maximum number of people without DL is 40. If all these 40 are males, then males without DL = 40. So, males with DL = Total Males - Males without DL = 70 - 40 = 30.) 3. **Calculate the maximum number of males with DL:** * The number of males with DL cannot exceed the total number of males (70). * The number of males with DL cannot exceed the total number of people with DL (80). * Therefore, the maximum number of males with DL = minimum(70, 80) = 70. 4. **Form the ratio:** * Ratio of minimum to maximum males with DL = 30 : 70 * Simplifying the ratio = 3 : 7 5. **Conclusion:** The ratio is 3 to 7, which corresponds to option C. The final answer is C.