In a test, a candidate attempted only 8 questions and secured 50% marks in each of the questions. If he obtained a total of 40% in the test and all questions in the test carried equal marks, how many questions were there in the test?
- A8
- B10Correct
- C15
- D16
Explanation
Let 'N' be the total number of questions in the test. Let 'M' be the marks allotted for each question. So, the total maximum marks for the test = N * M.
The candidate attempted only 8 questions. In each of these 8 questions, he secured 50% marks. Marks obtained in one question = 50% of M = 0.5 * M. Total marks obtained by the candidate = 8 questions * (0.5 * M marks/question) = 4M.
The candidate obtained a total of 40% in the test. This means (Total marks obtained) / (Total maximum marks) = 40%. So, (4M) / (N * M) = 0.40.
We can cancel 'M' from both the numerator and the denominator: 4 / N = 0.40.
Now, solve for N: N = 4 / 0.40 N = 4 / (4/10) N = 4 * (10/4) N = 10.
Therefore, there were 10 questions in the test.
Analyzing the options: A) 8: If there were 8 questions, and he got 50% in each of the 8, his total score would be 50%, not 40%. This is incorrect. B) 10: This matches our calculated value. If there are 10 questions (total 10M marks) and he scored 4M, his percentage is (4M/10M) * 100 = 40%. This is correct. C) 15: If there were 15 questions (total 15M marks) and he scored 4M, his percentage would be (4M/15M) * 100 = 26.67%, not 40%. This is incorrect. D) 16: If there were 16 questions (total 16M marks) and he scored 4M, his percentage would be (4M/16M) * 100 = 25%, not 40%. This is incorrect.
The final answer is B.

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