UPSC Prelims 2016·CSAT·Quantitative Aptitude·Arithmetic

30g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar Was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is

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Last updated 23 May 2026, 3:31 pm IST
  1. Asweeter than that in C
  2. Bsweeter than that in A
  3. Cas sweet as that in C
  4. Dless sweet than that in CCorrect

Explanation

To determine the sweetness of a solution, we need to calculate the concentration of sugar in each vessel. Concentration is the amount of sugar per unit volume of water. 1. Calculate concentration for each vessel: Vessel A: 30g sugar / 180ml water = 1/6 g/ml approx 0.1667 g/ml Vessel B: 40g sugar / 280ml water = 4/28 g/ml = 1/7 g/ml approx 0.1428 g/ml Vessel C: 20g sugar / 100ml water = 1/5 g/ml = 0.2 g/ml 2. Compare the concentrations: Concentration C (0.2 g/ml) is the highest, meaning it is the sweetest. Concentration A (0.1667 g/ml) is in the middle. Concentration B (0.1428 g/ml) is the lowest, meaning it is the least sweet. So, C > A > B in terms of sweetness. 3. Analyze the options for vessel B: A) sweeter than that in C: Incorrect, B (0.1428) is less sweet than C (0.2). B) sweeter than that in A: Incorrect, B (0.1428) is less sweet than A (0.1667). C) as sweet as that in C: Incorrect, B (0.1428) is not equal to C (0.2). D) less sweet than that in C: Correct, B (0.1428) is indeed less sweet than C (0.2). The final answer is D.
Quantitative Aptitude: 30g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar Was mixed in 280 ml of water in vessel B and 20 g of

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