A round archery target of diameter 1 m is marked with four scoring regions from the centre outwards as red, bl

Question

A round archery target of diameter 1 m is marked with four scoring regions from the centre outwards as red, blue, yellow and white. The radius of the red band is 0.20 m. The width of all the remaining bands is equal. If archers throw arrows towards the target, what is the probability, that the arrows fall in the red region of the archery target?

Accepted Answer

To find the probability, we need to divide the area of the red region by the total area of the archery target.

1. The total diameter of the target is 1 m, so the total radius is 0.50 m.
2. The radius of the red region is given as 0.20 m.
3. Area of a circle is calculated as pi multiplied by the square of the radius.
4. The area of the red region is pi times 0.20 squared, which equals 0.04 pi.
5. The total area of the target is pi times 0.50 squared, which equals 0.25 pi.
6. The probability is the ratio of these areas: 0.04 pi divided by 0.25 pi.
7. Canceling pi, we get 0.04 divided by 0.25.
8. This simplifies to 4 divided by 25, which equals 0.16.

The correct option is C.

Answer

0.4

Answer

0.2

Answer

0.16

Answer

0.04

Explanation

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