In adult Population or a city, 40% men and 30% women are married. What is the percentage of married adult population if no man marries more than one woman and no woman marries more than one man; and there are no widows and widowers?

Let M be the total number of men and W be the total number of women in the city. 1. Number of married men = 40% of M = 0.4M 2. Number of married women = 30% of W = 0.3W The problem states that "no man marries more than one woman and no woman marries more than one man; and there are no widows and widowers". This implies that the total number of married men must be equal to the total number of married women. Therefore, 0.4M = 0.3W From this equation, we can find the ratio of men to women: 4M = 3W M/W = 3/4 Let M = 3x and W = 4x for some common factor x. Now, calculate the total adult population: Total population = M + W = 3x + 4x = 7x Next, calculate the total number of married adults: Number of married men = 0.4 * (3x) = 1.2x Number of married women = 0.3 * (4x) = 1.2x Total married adults = 1.2x + 1.2x = 2.4x Finally, calculate the percentage of married adult population: Percentage = (Total married adults / Total population) * 100 Percentage = (2.4x / 7x) * 100 Percentage = (2.4 / 7) * 100 Percentage = (24 / 70) * 100 Percentage = (12 / 35) * 100 Percentage = 1200 / 35 To convert 1200/35 to a mixed fraction: 1200 divided by 35: 1200 / 35 = 240 / 7 (dividing numerator and denominator by 5) 240 divided by 7: 240 = 7 * 34 + 2 So, 240/7 = 34 and 2/7 The percentage of married adult population is 34 2/7%. Analyzing the options: A) 33 1/7% - Incorrect. B) 34% - Incorrect, as there's a remainder. C) 34 2/7% - Correct, matches our calculation. D) 35% - Incorrect. The final answer is C.