UPSC Prelims 2020·CSAT·Quantitative Aptitude·Arithmetic

A sum of Rs. 2,500 is distributed among X, Y and Z in the ratio 1/2 : 3/4 : 5/6. What is the difference between the maximum share and the minimum share?

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Last updated 23 May 2026, 3:31 pm IST
  1. A300
  2. B350
  3. C400Correct
  4. D450

Explanation

The correct answer is C. Here's a brief explanation: 1. Convert the ratio to whole numbers: The given ratio is 1/2 : 3/4 : 5/6. To simplify, find the Least Common Multiple (LCM) of the denominators (2, 4, 6), which is 12. Multiply each fraction by 12: X's share ratio = (1/2) * 12 = 6 Y's share ratio = (3/4) * 12 = 9 Z's share ratio = (5/6) * 12 = 10 So, the ratio X : Y : Z is 6 : 9 : 10. 2. Calculate the total number of ratio parts: 6 + 9 + 10 = 25 parts. 3. Determine the value of one ratio part: The total sum is Rs. 2,500. Value of one part = 2500 / 25 = Rs. 100. 4. Find the individual shares: X's share = 6 * 100 = Rs. 600 Y's share = 9 * 100 = Rs. 900 Z's share = 10 * 100 = Rs. 1,000 5. Identify the maximum and minimum shares: Maximum share = Rs. 1,000 (Z's share) Minimum share = Rs. 600 (X's share) 6. Calculate the difference: Difference = Maximum share - Minimum share = 1000 - 600 = Rs. 400. Therefore, the difference between the maximum share and the minimum share is Rs. 400.
Quantitative Aptitude: A sum of Rs. 2,500 is distributed among X, Y and Z in the ratio 1/2 : 3/4 : 5/6. What is the difference between the maxi

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