In the series _b_a_ba_b_abab_aab; fill in the six blanks ( _ ) using one of the following given four choices such that the series follows a specific order

The correct answer is D) ababab. Here's a brief explanation: 1. **Fill the blanks with option D (ababab):** When we fill the six blanks ( _ ) in the series _b_a_ba_b_abab_aab with 'ababab', the complete series becomes: a b b a a b a b b a b a b a b a a b 2. **Identify the pattern by grouping:** Divide the series into blocks of three characters: (abb) (aab) (abb) (aba) (bab) (aab) 3. **Analyze the composition of each block:** * Block 1: abb (1 'a', 2 'b's) * Block 2: aab (2 'a's, 1 'b') * Block 3: abb (1 'a', 2 'b's) * Block 4: aba (2 'a's, 1 'b') * Block 5: bab (1 'a', 2 'b's) * Block 6: aab (2 'a's, 1 'b') 4. **Observe the consistent pattern:** The series follows a clear alternating pattern where each block of three characters consistently alternates between having (1 'a' and 2 'b's) and (2 'a's and 1 'b'). 5. **Why other options are incorrect:** * **A) bababa:** Filling with this option results in "bbb..." at the start, which immediately breaks the observed (1a, 2b) / (2a, 1b) pattern. * **B) baabba:** This option starts with "bba aab aba...", where 'aba' (2a, 1b) follows 'aab' (2a, 1b), breaking the alternating pattern of character counts. * **C) bbaabb:** This option results in "bbb..." at the start, similar to A, breaking the pattern. Therefore, option D is the only choice that creates a consistent and logical pattern in the series.