In the series _b_a_ba_b_abab_aab; fill in the six blanks ( _ ) using one of the following given four choices such that the series follows a specific order
- Abababa
- Bbaabba
- Cbbaabb
- DabababCorrect
Explanation
The correct answer is D) ababab.
Here's a brief explanation:
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Fill the blanks with option D (ababab): When we fill the six blanks ( _ ) in the series _b_a_ba_b_abab_aab with 'ababab', the complete series becomes: a b b a a b a b b a b a b a b a a b
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Identify the pattern by grouping: Divide the series into blocks of three characters: (abb) (aab) (abb) (aba) (bab) (aab)
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Analyze the composition of each block:
- Block 1: abb (1 'a', 2 'b's)
- Block 2: aab (2 'a's, 1 'b')
- Block 3: abb (1 'a', 2 'b's)
- Block 4: aba (2 'a's, 1 'b')
- Block 5: bab (1 'a', 2 'b's)
- Block 6: aab (2 'a's, 1 'b')
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Observe the consistent pattern: The series follows a clear alternating pattern where each block of three characters consistently alternates between having (1 'a' and 2 'b's) and (2 'a's and 1 'b').
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Why other options are incorrect:
- A) bababa: Filling with this option results in "bbb..." at the start, which immediately breaks the observed (1a, 2b) / (2a, 1b) pattern.
- B) baabba: This option starts with "bba aab aba...", where 'aba' (2a, 1b) follows 'aab' (2a, 1b), breaking the alternating pattern of character counts.
- C) bbaabb: This option results in "bbb..." at the start, similar to A, breaking the pattern.
Therefore, option D is the only choice that creates a consistent and logical pattern in the series.

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