Model Answer
0 min readIntroduction
Sample size determination is a fundamental aspect of statistical research, ensuring that the collected data accurately represents the larger population and that the study's findings are reliable and generalizable. It is critical for efficient resource allocation and valid inference. The precision of an estimate, often expressed through a confidence interval and margin of error, directly depends on the sample size. This calculation becomes particularly important in quality control processes, such as estimating the average weight of cereal containers, where both statistical rigor and practical considerations of population size play a role.
1. Determining Sample Size for a Finite Population
To determine the required sample size for estimating the true weight of cereal containers from a finite population, we use the formula that incorporates the finite population correction factor (FPC). Given parameters:- Population size (N) = 5000
- Variance of weight ($\sigma^2$) = 121 grams
- Standard Deviation ($\sigma$) = $\sqrt{121}$ = 11 grams
- Estimate should be within (Margin of Error, E) = 2.5 grams
- Confidence Level = 99%
Step 1: Find the Z-score for 99% Confidence Level
For a 99% confidence level, the alpha ($\alpha$) value is 1 - 0.99 = 0.01. We need to find the Z-score that corresponds to an area of $\frac{\alpha}{2}$ in each tail of the normal distribution. This means we look for the Z-score corresponding to a cumulative probability of $1 - \frac{0.01}{2} = 1 - 0.005 = 0.995$. From standard Z-tables, the Z-score for a 99% confidence level is approximately 2.576. (Note: Some tables might approximate it as 2.58).Step 2: Calculate the Initial Sample Size (for infinite population assumption)
First, we calculate the sample size assuming an infinite population. This is often denoted as $n_0$. The formula for sample size when estimating a mean for an infinite population is: $n_0 = \frac{Z^2 \sigma^2}{E^2}$ Where:- Z = Z-score (2.576)
- $\sigma$ = Standard Deviation (11 grams)
- E = Margin of Error (2.5 grams)
Step 3: Apply the Finite Population Correction Factor
Since the population is finite (N = 5000), we need to adjust the initial sample size using the finite population correction (FPC) formula. The formula for sample size with finite population correction is: $n = \frac{n_0}{1 + \frac{n_0 - 1}{N}}$ Where:- $n_0$ = Initial sample size (1285)
- N = Population size (5000)
2. Change in Sample Size if Population is Assumed to be Infinite
If we assume the population to be infinite, the sample size required would be the initial sample size calculated in Step 2, which is $n_0 = 1285$. Explanation of Change: Yes, there will be a change in the size of the sample if we assume the population to be infinite. When dealing with a finite population, especially when the sample size is a significant proportion (typically more than 5%) of the total population, the finite population correction factor (FPC) is applied. The FPC reduces the calculated sample size because, in a finite population, sampling without replacement means that the probability of selecting subsequent items changes, and the variability in the sample estimates is actually lower than what would be assumed in an infinite population. Essentially, knowing more about a larger portion of the population reduces the uncertainty. Calculation of the Difference: Difference in sample size = Sample size (Infinite Population) - Sample size (Finite Population) Difference = $n_0 - n$ Difference = $1285 - 1023$ Difference = $262$ The sample size decreases by 262 units when accounting for the finite population of 5000 cereal containers, compared to assuming an infinite population. This reduction reflects the increased precision gained by sampling from a limited pool, where each selected item provides relatively more information about the overall population.The calculations are summarized in the table below:
| Parameter | Value |
|---|---|
| Population Size (N) | 5000 |
| Variance ($\sigma^2$) | 121 grams |
| Standard Deviation ($\sigma$) | 11 grams |
| Margin of Error (E) | 2.5 grams |
| Confidence Level | 99% |
| Z-score (Z) | 2.576 |
| Initial Sample Size ($n_0$, infinite population) | 1285 |
| Adjusted Sample Size (n, finite population) | 1023 |
| Change in Sample Size | 262 (decrease) |
Conclusion
The determination of an appropriate sample size is crucial for ensuring the statistical validity and practical feasibility of any research or quality control effort. For the cereal container weight estimation, the required sample size for a finite population of 5000 was found to be 1023. This is significantly lower than the 1285 samples that would be needed if the population were considered infinite. The finite population correction factor plays a vital role in reducing the sample size, recognizing the increased information gained when sampling from a relatively smaller, known population. Understanding and correctly applying these statistical principles allows for more efficient resource utilization while maintaining the desired level of confidence and precision in the estimates.
Answer Length
This is a comprehensive model answer for learning purposes and may exceed the word limit. In the exam, always adhere to the prescribed word count.