A rectangle has a perimeter of 50 meters. If its length is 13 metres more than its breadth, then its area is
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UPSC Civil Services preparation
- A124 m²
- B144 m²
- C114 m²Correct
- D104 m²
Explanation
To find the area of the rectangle, we first determine its dimensions using the given perimeter and the relationship between length and breadth.
Let the breadth be x meters.
Since the length is 13 meters more than the breadth, the length is x plus 13 meters.
The formula for the perimeter of a rectangle is 2 times the sum of length and breadth.
So, 2 times (x plus x plus 13) equals 50.
This simplifies to 2 times (2x plus 13) equals 50.
Dividing both sides by 2 gives 2x plus 13 equals 25.
Subtracting 13 from 25 gives 2x equals 12.
Dividing by 2 gives x equals 6.
Therefore, the breadth is 6 meters and the length is 6 plus 13, which is 19 meters.
The area of a rectangle is length times breadth.
Area equals 19 times 6, which is 114 square meters.

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