In 1930, a person’s age was 8 times that of his son. In 1938, the father’s age became ten times that of his son’s age in 1930. The ages of the son and father in 1940 were, respectively.

To solve this, let the son s age in 1930 be x and the father s age be 8x. In 1938, which is 8 years later, the father s age was 8x plus 8. According to the question, this age was 10 times the son s age in 1930, which was x. So, the equation is 8x plus 8 equals 10x. Subtracting 8x from both sides gives 2x equals 8. Therefore, x equals 4. In 1930: Son s age was 4. Father s age was 8 times 4, which is 32. To find their ages in 1940, we must add 10 years to their ages in 1930: Son s age in 1940: 4 plus 10 equals 14. Father s age in 1940: 32 plus 10 equals 42. The correct ages are 14 years and 42 years, matching option C.