If the radius of the earth were shrunk by one per cent, its mass remaining the same, the value of ‘g’ on the earth’s surface would
- Aincrease by 0.5%
- Bincrease by 2%Correct
- Cdecrease by 0.5%
- Ddecrease by 2%
Explanation
The value of acceleration due to gravity g is calculated using the formula g equals G times M divided by R squared, where G is the gravitational constant, M is the mass of the earth, and R is its radius.
Since the mass M remains constant, g is inversely proportional to the square of the radius R. In physics, for small percentage changes, the percentage change in g is approximately equal to minus two times the percentage change in R.
If the radius R shrinks by 1 percent, the change is negative 1 percent. Multiplying this by negative 2 results in a positive 2 percent. Therefore, the value of g increases by 2 percent. This happens because as the surface moves closer to the center of mass while the mass stays the same, the gravitational pull becomes stronger.

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