Four friends, A, B, C and D distribute some money among themselves in such a manner that A gets one less than

Question

Four friends, A, B, C and D distribute some money among themselves in such a manner that A gets one less than B, C gets 5 more than D, D gets 3 more than B. Who gets the smallest amount?

Accepted Answer

Let the amounts A, B, C, D get be represented by the same letters.

From the statements:
1. A gets one less than B: A = B - 1
2. C gets 5 more than D: C = D + 5
3. D gets 3 more than B: D = B + 3

Now, let's express all amounts in terms of B:
*   A = B - 1 (from statement 1)
*   B = B
*   D = B + 3 (from statement 3)
*   C = D + 5 = (B + 3) + 5 = B + 8 (substituting D from statement 3 into statement 2)

So, the amounts are:
A = B - 1
B = B
C = B + 8
D = B + 3

Comparing these values:
B - 1 (A) is clearly the smallest value among B, B+3, B+8.

Therefore, A gets the smallest amount.

Analysis of options:
A) A: A = B - 1. This is the smallest.
B) B: B = B. This is greater than A.
C) C: C = B + 8. This is the largest.
D) D: D = B + 3. This is greater than A and B.

The final answer is A.

Answer

A

Answer

B

Answer

C

Answer

D

Four friends, A, B, C and D distribute some money among themselves in such a manner that A gets one less than B, C gets 5 more than D, D gets 3 more than B. Who gets the smallest amount?

Explanation

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