UPSC Prelims 2015·CSAT·Quantitative Aptitude·Arithmetic

A cow costs more than 4 goats but less than 5 goats. If a goat costs between Rs. 600 and Rs. 800, which of the following is a most valid conclusion?

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  1. AA cow costs more than Rs. 2,500
  2. BA cow costs less than Rs. 3,600
  3. CA cow costs between Rs. 2,600 and Rs. 3,800
  4. DA cow costs between Rs. 2,400 and Rs. 4,000Correct

Explanation

Let C be the cost of a cow and G be the cost of a goat. From the problem statement: 1. C > 4G (A cow costs more than 4 goats) 2. C 4G and G > 600, the minimum value for 4G would be slightly more than 4 * 600 = 2400. So, C > 2400. To find the upper bound for C: Since C < 5G and G < 800, the maximum value for 5G would be slightly less than 5 * 800 = 4000. So, C < 4000. Combining these two bounds, we get: 2400 < C < 4000. This means a cow costs between Rs. 2,400 and Rs. 4,000. Now let's evaluate the options: A) A cow costs more than Rs. 2,500. This is not necessarily true. A cow could cost, for example, Rs. 2,450, which is between Rs. 2,400 and Rs. 4,000, but not more than Rs. 2,500. So, this is not a valid conclusion for all cases. B) A cow costs less than Rs. 3,600. This is not necessarily true. A cow could cost, for example, Rs. 3,700, which is between Rs. 2,400 and Rs. 4,000, but not less than Rs. 3,600. So, this is not a valid conclusion for all cases. C) A cow costs between Rs. 2,600 and Rs. 3,800. This range is narrower than our calculated range (2400 - 4000). It excludes possibilities like Rs. 2,500 or Rs. 3,900, which are valid based on the problem statement. So, this is not the most valid conclusion. D) A cow costs between Rs. 2,400 and Rs. 4,000. This option perfectly matches our calculated range (2400 < C < 4000). It is the most comprehensive and accurate conclusion based on all the given information. The final answer is D
Quantitative Aptitude: A cow costs more than 4 goats but less than 5 goats. If a goat costs between Rs. 600 and Rs. 800, which of the following

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