X and Y are natural numbers other than 1, and Y is greater than X. Which of the following represents the largest number?

Let's analyze each option based on the given conditions: X and Y are natural numbers other than 1, and Y > X. This implies X >= 2 and Y >= 3. 1. **Option B (X/Y):** Since Y > X, X/Y will always be a proper fraction, meaning 0 = 2, 1/X = 3 (as Y > X and X >= 2), 1/Y X, Y/X will always be greater than 1. *Example: If X=2, Y=3, then Y/X = 3/2 = 1.5.* 4. **Option A (XY):** This is the product of two natural numbers, both greater than or equal to 2. Since X >= 2 and Y >= 3, XY >= 2 * 3 = 6. This value will always be greater than or equal to 6. *Example: If X=2, Y=3, then XY = 2 * 3 = 6.* **Comparison:** Options B and D are always less than 1. Option C is always greater than 1. Option A is always greater than or equal to 6. To confirm A is the largest, we compare A and C: We need to compare XY with Y/X. Multiply both sides by X (since X is a natural number, X > 0, so the inequality direction doesn't change): XY * X vs Y/X * X X^2 * Y vs Y Divide both sides by Y (since Y is a natural number, Y > 0, so the inequality direction doesn't change): X^2 vs 1 Since X is a natural number other than 1, X must be at least 2. Therefore, X^2 >= 2^2 = 4. Since X^2 >= 4, X^2 is always greater than 1. This proves that XY is always greater than Y/X. Therefore, XY (Option A) is the largest number. The final answer is $\boxed{A}$