UPSC Prelims 2024·CSAT·Quantitative Aptitude·Arithmetic

Five friends P. O, X, Y and Z purchased some notebooks. The relevant information is given below: 1. Z purchased 8 notebooks more than X did. 2. P and Q together purchased 21 notebooks. 3. O purchased 5 notebooks less than P did. 4. X and Y together purchased 28 notebooks. 5. P purchased 5 notebooks more than X did. If each notebook is priced 40, then what is the total cost of all the notebooks?

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Last updated 23 May 2026, 3:31 pm IST
  1. A2,600Correct
  2. B2,400
  3. C2,360
  4. D2,320

Explanation

Let P, Q, O, X, Y, Z be the number of notebooks purchased by each friend. We translate the given information into equations: 1. Z = X + 8 2. P + Q = 21 3. O = P - 5 4. X + Y = 28 5. P = X + 5 Our goal is to find the total number of notebooks (P + Q + O + X + Y + Z) and then multiply by the price per notebook (40). Let's express all variables in terms of X: From (5): P = X + 5 Substitute P into (3): O = (X + 5) - 5 = X Substitute P into (2): (X + 5) + Q = 21 => Q = 21 - X - 5 => Q = 16 - X From (4): Y = 28 - X From (1): Z = X + 8 Now we have all quantities in terms of X: P = X + 5 Q = 16 - X O = X X = X Y = 28 - X Z = X + 8 Total number of notebooks = P + Q + O + X + Y + Z Total = (X + 5) + (16 - X) + (X) + (X) + (28 - X) + (X + 8) Group the X terms and constant terms: Total = (X - X + X + X - X + X) + (5 + 16 + 28 + 8) Total = 2X + 57 The total cost is 40 times the total number of notebooks: Total Cost = 40 * (2X + 57) = 80X + 2280 Now, we check the options to find the value of X that leads to one of the answers. The number of notebooks must be a non-negative integer. A) If Total Cost = 2600: 80X + 2280 = 2600 80X = 2600 - 2280 80X = 320 X = 320 / 80 = 4 If X = 4, then P=9, Q=12, O=4, X=4, Y=24, Z=12. All these are non-negative integers, satisfying all conditions. Total notebooks = 2(4) + 57 = 8 + 57 = 65. Total cost = 65 * 40 = 2600. B) If Total Cost = 2400: 80X + 2280 = 2400 => 80X = 120 => X = 1.5 (Not an integer, so not valid). C) If Total Cost = 2360: 80X + 2280 = 2360 => 80X = 80 => X = 1. (This is an integer and valid. P=6, Q=15, O=1, X=1, Y=27, Z=9. Total notebooks = 59. Total cost = 59*40 = 2360. This implies the question might be ambiguous as both A and C are mathematically possible under standard interpretations. However, since A is given as the correct answer, we proceed with X=4). D) If Total Cost = 2320: 80X + 2280 = 2320 => 80X = 40 => X = 0.5 (Not an integer, so not valid). Based on the options, X=4 yields a total cost of 2600, which corresponds to option A. The final answer is A) 2,600.
Quantitative Aptitude: Five friends P. O, X, Y and Z purchased some notebooks. The relevant information is given below: 1. Z purchased 8 notebo

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