A 3-digit number ABC, on multiplication with D gives 37DD where A, B, C and D are different non-zero digits. W

Question

A 3-digit number ABC, on multiplication with D gives 37DD where A, B, C and D are different non-zero digits. What is the value of A+B+C?

Accepted Answer

To solve this, we look at the equation ABC x D = 37DD.

First, we find the range for D. Since the product starts with 37, if D were 3, the maximum product would be 999 x 3 = 2997, which is too small. If D were 6, the minimum product would be 123 x 6 = 738, which is too large. Therefore, D must be 4 or 5.

If D is 5, the product 37DD would be 3755. Dividing 3755 by 5 gives 751. Here, ABC is 751. However, the digits must be different and non zero. In 751 and 5, the digit 5 repeats. This violates the rule that A, B, C, and D are different digits.

If D is 4, the product 37DD would be 3744. Dividing 3744 by 4 gives 936. Here, ABC is 936 and D is 4. All digits 9, 3, 6, and 4 are different and non zero. This satisfies all conditions.

Therefore, A = 9, B = 3, and C = 6.
The sum A + B + C = 9 + 3 + 6 = 18.

The correct option is A.

Answer

18

Answer

16

Answer

15

Answer

Cannot be determined due to insufficient data

A 3-digit number ABC, on multiplication with D gives 37DD where A, B, C and D are different non-zero digits. What is the value of A+B+C?

Explanation

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