A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 m ahead of th

Question

A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 m ahead of the policeman, then the time required for the policeman to catch the thief will be

Accepted Answer

The correct answer is B. Here's a brief explanation:

1.  Calculate the relative speed: The policeman is chasing the thief, so their relative speed is the difference between their speeds.
    Relative speed = Policeman's speed - Thief's speed = 10 km/hr - 8 km/hr = 2 km/hr.

2.  Convert units for consistency: The distance is in meters (100 m) and the options are in minutes. Let's convert the relative speed from km/hr to m/min.
    2 km/hr = 2 * 1000 meters / 60 minutes = 2000 m / 60 min = 100/3 m/min.

3.  Calculate the time taken: Time = Distance / Relative Speed.
    Time = 100 m / (100/3 m/min) = 100 * (3/100) min = 3 minutes.

Therefore, the policeman will catch the thief in 3 minutes.

Analyzing the options:
A) 2 min: Incorrect. This would imply a higher relative speed or a shorter distance.
B) 3 min: Correct, as calculated above.
C) 4 min: Incorrect. This would imply a lower relative speed or a longer distance.
D) 6 min: Incorrect. This would imply a much lower relative speed or a significantly longer distance.

Answer

2 min

Answer

3 min

Answer

4 min

Answer

6 min

A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 m ahead of the policeman, then the time required for the policeman to catch the thief will be

Explanation

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