Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and g

Question

Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by

Accepted Answer

Initially, each of the six boys (A, B, C, D, E, F) has 10 cards.

Let's track the card changes:
1.  F borrows 2 from A:
    A = 10 - 2 = 8
    F = 10 + 2 = 12

2.  F gives 5 to C:
    F = 12 - 5 = 7
    C = 10 + 5 = 15

3.  C gives 3 to B:
    C = 15 - 3 = 12
    B = 10 + 3 = 13

4.  B gives 6 to D:
    B = 13 - 6 = 7
    D = 10 + 6 = 16

5.  D passes 1 to E:
    D = 16 - 1 = 15
    E = 10 + 1 = 11

Final card counts:
A = 8
B = 7
C = 12
D = 15
E = 11
F = 7

Number of cards possessed by D and E = D + E = 15 + 11 = 26.

Now, let's check the options:
A) A, B and C = 8 + 7 + 12 = 27 (Not equal to 26)
B) B, C and F = 7 + 12 + 7 = 26 (Equal to 26)
C) A, B and F = 8 + 7 + 7 = 22 (Not equal to 26)
D) A, C and F = 8 + 12 + 7 = 27 (Not equal to 26)

Therefore, the number of cards possessed by D and E is equal to the number of cards possessed by B, C and F.

The final answer is B.

Answer

A, B and C

Answer

B, C and F

Answer

A, B and F

Answer

A, C and F

Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by

Explanation

Related questions