Rakesh and Rajesh together bought 10 balls and 10 rackets. Rakesh spent 1300 and Rajesh spent 1500. If each racket costs three times a ball does, then what is the price of a racket?

Let 'b' be the price of a ball and 'r' be the price of a racket. 1. Calculate the total money spent: Rakesh spent 1300 and Rajesh spent 1500. So, total money spent = 1300 + 1500 = 2800. 2. Identify the total items bought: Together, they bought 10 balls and 10 rackets. 3. Formulate an equation for the total cost: The total cost of 10 balls and 10 rackets is 10b + 10r. So, 10b + 10r = 2800. Divide the entire equation by 10: b + r = 280. 4. Use the given relationship between prices: Each racket costs three times a ball, which means r = 3b. 5. Substitute the relationship into the equation: Replace 'r' with '3b' in the equation b + r = 280. b + (3b) = 280 4b = 280 b = 280 / 4 b = 70. So, the price of a ball is Rs 70. 6. Calculate the price of a racket: Since r = 3b, then r = 3 * 70 = 210. Therefore, the price of a racket is Rs 210. Analyzing the options: A) Rs 70: This is the price of a ball, not a racket. B) Rs 90: This is incorrect. C) Rs 210: This matches our calculated price for a racket. D) Rs 240: This is incorrect. The final answer is C.