A and B are two heavy steel blocks. If B is placed on the top of A, the weight increases by 60%. How much weight will reduce with respect to the total weight of A and B, if B is removed from the top of A?

Here's a brief explanation: 1. Let the weight of block A be W_A. 2. When B is placed on A, the total weight is W_A + W_B. 3. The problem states this total weight increases by 60% with respect to A. So, W_A + W_B = W_A + 0.60 * W_A = 1.60 * W_A. 4. From this, we can deduce W_B = 0.60 * W_A. 5. The total weight of A and B is W_A + W_B = W_A + 0.60 * W_A = 1.60 * W_A. 6. When B is removed, the weight reduces by W_B. 7. We need to find the percentage reduction with respect to the total weight of A and B (which is 1.60 * W_A). 8. Percentage reduction = (Weight reduced / Total weight of A and B) * 100 = (W_B / (1.60 * W_A)) * 100 = (0.60 * W_A / (1.60 * W_A)) * 100 = (0.60 / 1.60) * 100 = (6 / 16) * 100 = (3 / 8) * 100 = 0.375 * 100 = 37.5% Analyzing the options: A) 60%: This is the percentage increase in weight when B is added, relative to A's weight, not the reduction relative to the combined weight. B) 45.50%: Incorrect calculation. C) 40%: Incorrect calculation. D) 37.50%: This matches our calculation. The final answer is D.