In an examination, A has scored 20 marks more than B. If B has scored 5% less marks than A, how much has B sco

Question

In an examination, A has scored 20 marks more than B. If B has scored 5% less marks than A, how much has B scored?

Accepted Answer

Let A's score be 'a' and B's score be 'b'.

From the first statement: A has scored 20 marks more than B.
a = b + 20  (Equation 1)

From the second statement: B has scored 5% less marks than A.
This means B's score is 95% of A's score.
b = 0.95 * a  (Equation 2)

Substitute Equation 1 into Equation 2:
b = 0.95 * (b + 20)
b = 0.95b + 0.95 * 20
b = 0.95b + 19

Subtract 0.95b from both sides:
b - 0.95b = 19
0.05b = 19

To find b, divide 19 by 0.05:
b = 19 / 0.05
b = 19 / (5/100)
b = 19 * (100/5)
b = 19 * 20
b = 380

So, B has scored 380 marks.

Let's check:
If B = 380, then A = 380 + 20 = 400.
Is B's score (380) 5% less than A's score (400)?
Difference = 400 - 380 = 20.
Percentage less = (20 / 400) * 100 = (1/20) * 100 = 5%.
The conditions are satisfied.

The final answer is B) 380.

Answer

360

Answer

380

Answer

400

Answer

420

In an examination, A has scored 20 marks more than B. If B has scored 5% less marks than A, how much has B scored?

Explanation

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