Seeta and Geeta go for a swim after a gap of every 2 days and every 3 days respectively. If on 1st January both of them went for a swim together, when will they go together next?

The problem requires finding the next common day for two events that occur at regular intervals. This is a classic application of the Least Common Multiple (LCM). 1. **Understand the frequency for Seeta:** Seeta goes for a swim "after a gap of every 2 days". In the context of such problems, this is typically interpreted as swimming every 2 days. So, if she swims on Day 1 (1st January), her subsequent swim days will be: 1 + 2 = 3rd January 3 + 2 = 5th January 5 + 2 = 7th January And so on. Seeta's swim days: 1st, 3rd, 5th, 7th, 9th, ... January. 2. **Understand the frequency for Geeta:** Geeta goes for a swim "after a gap of every 3 days". This is interpreted as swimming every 3 days. So, if she swims on Day 1 (1st January), her subsequent swim days will be: 1 + 3 = 4th January 4 + 3 = 7th January 7 + 3 = 10th January And so on. Geeta's swim days: 1st, 4th, 7th, 10th, 13th, ... January. 3. **Find the next common day:** Both Seeta and Geeta swam together on 1st January. We need to find the next day they will swim together. We look for the next common day in their schedules: Seeta's days: 1, 3, 5, **7**, 9, ... Geeta's days: 1, 4, **7**, 10, ... The next common day after 1st January is 7th January. 4. **Using LCM (alternative method):** The interval for Seeta is 2 days. The interval for Geeta is 3 days. To find when they will next go together, we find the Least Common Multiple (LCM) of their intervals. LCM(2, 3) = 6. This means they will go together again 6 days after their last common swim. Last common swim: 1st January. Next common swim: 1st January + 6 days = 7th January. 5. **Analyze the options:** A) 7th January: This matches our calculation. B) 8th January: Incorrect. C) 12th January: Incorrect. D) 13th January: This would be the answer if "after a gap of N days" meant an interval of N+1 days (e.g., Seeta swims every 3 days, Geeta every 4 days, LCM(3,4)=12, so 1st Jan + 12 days = 13th Jan). However, given the options and typical interpretation in such questions, the "every N days" interpretation is intended. The final answer is A.