X, Y and Z are three contestants in a race of 1000 m. Assume that all run with different uniform speeds. X giv

Question

X, Y and Z are three contestants in a race of 1000 m. Assume that all run with different uniform speeds. X gives Y a start of 40 m and X gives Z a start of 64 m. If Y and Z were to compete in a race of 1000 m, how many metres start will Y give to Z?

Accepted Answer

Here's a brief explanation:

1.  **X vs. Y:** When X runs 1000m, Y runs 1000m - 40m = 960m. (This means Y's speed is 960/1000 times X's speed).
2.  **X vs. Z:** When X runs 1000m, Z runs 1000m - 64m = 936m. (This means Z's speed is 936/1000 times X's speed).
3.  **Y vs. Z:** We need to find the relative distance Y covers compared to Z in the same amount of time. From steps 1 and 2, in the time X runs 1000m, Y runs 960m and Z runs 936m.
    So, when Y runs 960m, Z runs 936m.
4.  **Calculate the start:** If Y were to run a full 1000m race, how far would Z run?
    Distance Z runs = (936 / 960) * 1000m
    = (117 / 120) * 1000m (dividing 936 and 960 by 8)
    = (117 / 12) * 100m
    = 975m
5.  Therefore, when Y finishes 1000m, Z has run 975m. Y gives Z a start of 1000m - 975m = 25m.

The final answer is B) 25.

Answer

20

Answer

25

Answer

30

Answer

35

X, Y and Z are three contestants in a race of 1000 m. Assume that all run with different uniform speeds. X gives Y a start of 40 m and X gives Z a start of 64 m. If Y and Z were to compete in a race of 1000 m, how many metres start will Y give to Z?

Explanation

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