UPSC Prelims 2022·CSAT·Quantitative Aptitude·Arithmetic

On one side of a 1.01 km long road, 101 plants are planted at equal distance from each other. What is the total distance between 5 consecutive plants?

Dalvoy logo
Reviewed by Dalvoy
UPSC Civil Services preparation
Last updated 23 May 2026, 3:31 pm IST
  1. A40 m
  2. B40.4 mCorrect
  3. C50 m
  4. D50.5 m

Explanation

The road length is 1.01 km, which is 1010 meters. There are 101 plants planted at equal distances. If there are 'n' plants, there are 'n-1' gaps between them. So, the number of gaps between 101 plants is 101 - 1 = 100 gaps. The distance of one gap (distance between two consecutive plants) is: Total road length / Number of gaps = 1010 m / 100 = 10.1 m. We need to find the total distance between 5 consecutive plants. If you have 5 consecutive plants (P1, P2, P3, P4, P5), there are 4 gaps between them: P1 --gap1-- P2 --gap2-- P3 --gap3-- P4 --gap4-- P5 Total distance between 5 consecutive plants = 4 gaps * distance of one gap = 4 * 10.1 m = 40.4 m. Analyzing the options: A) 40 m: Incorrect. This would imply a gap of 10 m. B) 40.4 m: Correct, as calculated above. C) 50 m: Incorrect. This would imply 5 gaps of 10 m, or a gap of 12.5 m. D) 50.5 m: Incorrect. This would imply 5 gaps of 10.1 m, mistakenly counting 5 gaps for 5 plants. The final answer is B.
Quantitative Aptitude: On one side of a 1.01 km long road, 101 plants are planted at equal distance from each other. What is the total distance
ShareWhatsAppXTelegram

Related questions

More UPSC Prelims practice from the same subject and topic.