Five friends P , Q , X , Y and Z purchased some notebooks. The relevant information is given below: 1. Z Purchased 8 notebooks more than X did. 2. P and Q Together purchased 21 notebooks. 3. Q purchased 5 notebooks less than P did. 4. X and Y Together purchased 28 notebooks. 5. P Purchased 5 notebooks more than X did. If each notebook is priced 40, then what is the total cost of all the notebooks?
- A2,600Correct
- B2,400
- C2,360
- D2,320
Explanation
Let p, q, x, y, z be the number of notebooks purchased by P, Q, X, Y, Z respectively.
From the given information:
- z = x + 8
- p + q = 21
- q = p - 5
- x + y = 28
- p = x + 5
Step-by-step calculation:
-
Solve for P and Q using statements 2 and 3: Substitute (3) into (2): p + (p - 5) = 21 => 2p - 5 = 21 => 2p = 26 => p = 13. Using p = 13 in (3): q = 13 - 5 => q = 8. So, P purchased 13 notebooks and Q purchased 8 notebooks.
-
Solve for X using statement 5 and p = 13: 13 = x + 5 => x = 13 - 5 => x = 8. So, X purchased 8 notebooks.
-
Solve for Z using statement 1 and x = 8: z = 8 + 8 => z = 16. So, Z purchased 16 notebooks.
-
Solve for Y using statement 4 and x = 8: 8 + y = 28 => y = 28 - 8 => y = 20. So, Y purchased 20 notebooks.
Total notebooks purchased = p + q + x + y + z = 13 + 8 + 8 + 20 + 16 = 65 notebooks.
Each notebook is priced at 40. Total cost = Total notebooks * Price per notebook = 65 * 40 = 2600.
Therefore, the total cost of all the notebooks is 2,600.
The final answer is A) 2,600.

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