When 70% of a number x is added to another number y, the sum becomes 165% of the value of y. When 60% of the n

Question

When 70% of a number x is added to another number y, the sum becomes 165% of the value of y. When 60% of the number x is added to another number z, then the sum becomes 165% of the value of z. which one of the following is correct?

Accepted Answer

Let's break down the problem into two statements: Statement 1: "When 70% of a number x is added to another number y, the sum becomes 165% of the value of y." This can be written as: 0.7x + y = 1.65y Subtract y from both sides: 0.7x = 1.65y - y 0.7x = 0.65y To compare x and y, we can write x = (0.65 / 0.7)y = (65 / 70)y = (13 / 14)y. Since 13/14 is less than 1, it implies that x is less than y (x < y). Statement 2: "When 60% of the number x is added to another number z, then the sum becomes 165% of the value of z." This can be written as: 0.6x + z = 1.65z Subtract z from both sides: 0.6x = 1.65z - z 0.6x = 0.65z To compare x and z, we can write x = (0.65 / 0.6)z = (65 / 60)z = (13 / 12)z. Since 13/12 is greater than 1, it implies that x is greater than z (x > z). Combining the two findings: From Statement 1: x < y From Statement 2: x > z (which means z < x) Putting these together, we get z < x < y. Now let's check the options: A) z < x < y - This matches our derived relationship. B) x < y < z - Incorrect. C) y < x < z - Incorrect. D) z < y < x - Incorrect. Therefore, option A is correct. The final answer is A.

Answer

z < x < y

Answer

x < y < z

Answer

y < x < z

Answer

z < y < x

When 70% of a number x is added to another number y, the sum becomes 165% of the value of y. When 60% of the number x is added to another number z, then the sum becomes 165% of the value of z. which one of the following is correct?

Explanation

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