Consider the sequence given below: 4/12/95, 1/1/96, 29/1/96, 26/2/96, _ _ _ _ _ What is the next term of the series?

The pattern in the sequence is a consistent difference of 28 days between consecutive dates.

1. From 4/12/95 to 1/1/96: (31-4) days in Dec 1995 + 1 day in Jan 1996 = 27 + 1 = 28 days.
2. From 1/1/96 to 29/1/96: 29 - 1 = 28 days.
3. From 29/1/96 to 26/2/96: 1996 is a leap year, so February has 29 days. (31-29) days in Jan 1996 + 26 days in Feb 1996 = 2 + 26 = 28 days.

Following this pattern, we need to add 28 days to the last given date, 26/2/96. February 1996 has 29 days. Days remaining in February from 26/2/96 = 29 - 26 = 3 days. We need to add 28 days in total. After using 3 days from February, the remaining days to add are 28 - 3 = 25 days. These 25 days will fall in March 1996. Therefore, the next term is 25/3/96.

Option B is 25/3/96, which matches our calculation.