UPSC Prelims 2019·CSAT·Quantitative Aptitude·Arithmetic

If the numerator and denominator of a proper fraction are increased by the same positive quantity which is greater than zero, the resulting fraction is

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  1. Aalways less than the original fractionCorrect
  2. Balways greater than the original fraction
  3. Calways equal to the original fraction
  4. Dsuch that nothing can be claimed definitely

Explanation

Actually, there is a small correction needed. For a proper fraction, the resulting fraction is always greater than the original fraction, which would make Option B the correct answer. However, to explain why the relationship changes in a specific direction, let us look at the logic. A proper fraction is one where the numerator is less than the denominator, such as 1 divided by 2. If we add a positive quantity, for example 1, to both the numerator and denominator, the fraction becomes 2 divided by 3. Comparing the two, 2 divided by 3 is approximately 0.66, which is greater than 1 divided by 2, which is 0.5. Mathematically, when you increase both parts of a proper fraction by the same positive amount, the ratio moves closer to 1. Since a proper fraction starts at a value less than 1, increasing it towards 1 means the value is increasing. If the original question or key insists that A is correct, it would imply the fraction was an improper fraction where the numerator is greater than the denominator. For a proper fraction, the resulting fraction is always greater than the original.
Quantitative Aptitude: If the numerator and denominator of a proper fraction are increased by the same positive quantity which is greater than

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