UPSC Prelims 2019·CSAT·Logical Reasoning·Arrangement and Puzzles

A' started from his house and walked 20 m towards East, where his friend 13' joined him. They together walked 10 m in the same direction. Then 'A' turned left while 'B' turned right and travelled 2 m and 8 m respectively. Again 'B' turned left to travel 4 m followed by 5 m to his right to reach his office. 'A' turned right and travelled 12 m to reach his office. What is the shortest distance between the two offices?

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Last updated 23 May 2026, 3:31 pm IST
  1. A15
  2. B17Correct
  3. C19
  4. D20

Explanation

To find the shortest distance between the two offices, we first track the coordinates of A and B starting from the origin (0,0). Initial Movement: A starts at (0,0) and walks 20 m East to (20,0). B joins him. They walk 10 m more East to (30,0). Path of A: From (30,0), A turns left (North) and walks 2 m to (30,2). Then A turns right (East) and walks 12 m to reach his office at (42,2). Path of B: From (30,0), B turns right (South) and walks 8 m to (30,-8). Then B turns left (East) and walks 4 m to (34,-8). Finally, B turns right (South) and walks 5 m to reach his office at (34,-13). Shortest Distance Calculation: We use the distance formula between A (42,2) and B (34,-13). Difference in x-coordinates: 42 minus 34 equals 8. Difference in y-coordinates: 2 minus negative 13 equals 15. The shortest distance is the square root of (8 squared plus 15 squared). 8 squared is 64 and 15 squared is 225. 64 plus 225 equals 289. The square root of 289 is 17. The shortest distance between the two offices is 17 m. Therefore, option B is correct.
Logical Reasoning: A' started from his house and walked 20 m towards East, where his friend 13' joined him. They together walked 10 m in th

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